9x^2=425

Solution for 9x^2=425 equation:

9x^2=425

We move all terms to the left:

9x^2-(425)=0

a = 9; b = 0; c = -425;
Δ = b2-4ac
Δ = 02-4·9·(-425)
Δ = 15300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15300}=\sqrt{900*17}=\sqrt{900}*\sqrt{17}=30\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{17}}{2*9}=\frac{0-30\sqrt{17}}{18}
=-\frac{30\sqrt{17}}{18}
=-\frac{5\sqrt{17}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{17}}{2*9}=\frac{0+30\sqrt{17}}{18}
=\frac{30\sqrt{17}}{18}
=\frac{5\sqrt{17}}{3}
$